5x^2+6x-1=(5x-1)(x+1)

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Solution for 5x^2+6x-1=(5x-1)(x+1) equation: 



5x^2+6x-1=(5x-1)(x+1)

We move all terms to the left:

5x^2+6x-1-((5x-1)(x+1))=0

We multiply parentheses ..

5x^2-((+5x^2+5x-1x-1))+6x-1=0



We calculate terms in parentheses: -((+5x^2+5x-1x-1)), so:

(+5x^2+5x-1x-1)

We get rid of parentheses

5x^2+5x-1x-1

We add all the numbers together, and all the variables

5x^2+4x-1

Back to the equation:

-(5x^2+4x-1)



We add all the numbers together, and all the variables

5x^2+6x-(5x^2+4x-1)-1=0

We get rid of parentheses

5x^2-5x^2+6x-4x+1-1=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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